8x^2-40=10

Solution for 8x^2-40=10 equation:

8x^2-40=10

We move all terms to the left:

8x^2-40-(10)=0

We add all the numbers together, and all the variables

8x^2-50=0

a = 8; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·8·(-50)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*8}=\frac{-40}{16}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*8}=\frac{40}{16}
=2+1/2
$